gulp-sass error
By default gulp-sass never throws a clean error exit code (1). A lot of CI systems require this exit code to fail a build. This package provides a function to do so.
Installation
npm install --save gulp-sass-error
Usage
Using es2015 modules / typescript:
import { gulpSassError } from 'gulp-sass-error';
const throwError = true;
gulp.task('sass', () => {
return gulp.src('web/css/*.scss')
.pipe(
sass()
/** Instead of sass.logError you use gulpSassError */
.on('error', gulpSassError(throwError))
)
.pipe(postcss(config.postcss))
.pipe(gulp.dest('web/css'));
});Using require:
const { gulpSassError } = require('gulp-sass-error');
const throwError = true;
gulp.task('sass', () => {
return gulp.src('web/css/*.scss')
.pipe(
sass()
/** Instead of sass.logError you use gulpSassError */
.on('error', gulpSassError(throwError))
)
.pipe(postcss(config.postcss))
.pipe(gulp.dest('web/css'));
});
