Rereplace
Rereplace is a module to transform a string matching a regex A into a string matching a regex B (and vice-versa).
It automatically detects the regex of the input and transfers it into the other regex format.
You just need to write down 2 correct regexes with matching named groups and the package will handle the transformations.
Here is a good site to try Python regexes.
Works with Python 3+
Getting started
pip install rereplace
from rereplace import RegexReplace
rer = RegexReplace(r"^(?P<A>\d{2})\.(?P<B>\d{2})$",r"^(?P<B>\d{2})(?P<A>\d{2})$")
rer.replace("01.02")
# => 0201
rer.replace("0201")
# => 01.02It is also possible to reuse some named groups multiple times (unlike the python re module) :
from rereplace import RegexReplace
rer = RegexReplace(r"^(?P<WORD>.{5})$",r"^(?P<WORD>.{5})(?P<WORD>.{5})(?P<WORD>.{5})$")
rer.replace("HELLO")
# => HELLOHELLOHELLO
rer.replace("HELLOHELLOHELLO")
# => HELLOOther examples :
from rereplace import RegexReplace
rer = RegexReplace(r"^(?P<WORD1>.{3})-(?P<CODE>\d{3})-(?P<WORD2>.{4})-(?P<CODE2>\d{3})-(?P<WORD3>.{5})$",
r"^(?P<WORD1>.{3})/(?P<CODE2>\d{3})/(?P<WORD2>.{4})/(?P<CODE>\d{3})/(?P<WORD3>.{5})$")
rer.replace("ABC-123-ABCD-456-ABCDE")
# => ABC/456/ABCD/123/ABCDE
rer.replace("ABC/456/ABCD/123/ABCDE")
# => ABC-123-ABCD-456-ABCDEfrom rereplace import RegexReplace
rer = RegexReplace(r"^(?P<DD>\d{2})-(?P<MM>\d{2})-(?P<YYYY>\d{4})$",
r"^(?P<MM>\d{2})/(?P<DD>\d{2})/(?P<YYYY>\d{4})$")
rer.replace("31-12-2017")
# => "12/31/2017"
rer.replace("12/31/2017")
# => "31-12-2017"
