from spiget import *

# Check if there's a resource available with a specific name
if is_valid_resource("Commons):
	#Execute your code here

#You can also operate on resources via their ID 
#(15290 is Commons, as above)
if is_valid_resource(15290):
	#Execute your code here.
    
#Get resource retrieves the JSON Details for a specific resurce
json = get_resource("Commons")

#Same as above
json = get_resource(15290)

#Let's see this output!
print(json)

#Below is the result of retrieving the "Commons" Resource, above!
{
'external': False,
'category': {'id': 26}, 
'link': 'https://www.spigotmc.org/resources/15290', 
'lastUpdate': 'Dec 15, 2015 at 9:35 PM', 
'id': 15290, 
'download': 'https://www.spigotmc.org/resources/commons.15290/download?version=58055',
'author': {
	'id': 3629
 },
 'versions': ['1.8.8', '1.8.8-1', '1.8.8-2'],
 'version': '1.8.8-2',
 'tag': 'An all in one Framework (API) providing the Essentials for server owners, and developers!',
 'icon': '',
 'file': {
 	'size': '1 MB',
    'type': '.jar'
  },
  'name': 'Commons'
}

#Here's how to achieve the same thing with an Object!
resource = SpigotResource.from_id(15290)
#or
resource = SpigotResource.from_name("Commons")
#or even from json directly!
resource = SpigotResource.from_json(get_resource("Commons"))

#Not calling one of the static methods, and initializing the object
#directly requires JSON to be passed.
resource = SpigotResource(get_resource(15290))

#Printing will print the same data as previously..

#Lets get an author!
author = SpigotAuthor.from_username("MumbosHut")

#How about a category?!
category = SpigotCategory.from_id(4)