from htmltagparse import titleFromUri

websiteTitle = titleFromUri("https://github.com/")
print(websiteTitle) # output: GitHub: Let’s build from here · GitHub

from htmltagparse import build

brave = build.fromUri("https://search.brave.com/", timeout=20)
print(brave.tags) #list of tags found on the specified page
print(brave.searchTag("footer")) #displays a list of innerHtml content to the footer tags
print(brave.searchTag("footer", htmlFormat=False)[0]) #output: © Brave Software Brave Search API Summarizer Helpful answers Report a security issue

from htmltagparse import HtmlPage
from requests import get

htmlContent = get("https://duckduckgo.com/").text
ddg = HtmlPage(htmlContent)
print(list(ddg.sources)) #output: ['script']

from htmltagparse import build
import re

videoId = ""
page = build.fromUri("https://www.youtube.com/watch?v=%s" % videoId)
try:
  #NOTE: the regex function already has re's MULTILINE and DOTALL flags in use
  #get a list of tags to the youtube video via this regex pattern
  videoTags = page.regex(r"\"keywords\":(?P<tags>\[.*?),\"channelId\":").group("tags")
  #converting from string to array
  videoTags = re.findall(r"(?:\"|\')(?P<tag>.*?)(?:\'|\")(?:\,|\])", videoTags)
except:
  videoTags = "no tags found"

print(videoTags)

import htmltagparse

#youtube video id
videoId = ""
video = htmltagparse.build.fromUri("https://www.youtube.com/watch?v=%s" % videoId)

for i in video.metadata:
  if i.get("name") == "keywords":
    tags = i.get("content").split(", ")
    break
print(i)